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#1
December 2nd, 2005, 06:34 PM
posted to microsoft.public.access.reports
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How to total my DateDiff Field in a report
In my report I need to total my DateDiff field (=DateDiff("d",[Date
Rejected],[Date Completed]) in the header. It is a number of days, but when I try =Sum([DateDiff("d",[Date Rejected],[Date Completed])]) the expression is too complicated. How can I get my report to total all the days? 
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#2
December 2nd, 2005, 09:18 PM
posted to microsoft.public.access.reports
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How to total my DateDiff Field in a report
"Marcy@airproducts"
wrote: In my report I need to total my DateDiff field (=DateDiff("d",[Date Rejected],[Date Completed]) in the header. It is a number of days, but when I try =Sum([DateDiff("d",[Date Rejected],[Date Completed])]) the expression is too complicated. How can I get my report to total all the days? There is an extra ] in that expression. Also make sure that [Date Rejected] and [Date Completed] are **fields** in the report's record source table/query and not controls on the report. -- Marsh MVP [MS Access]
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#3
December 2nd, 2005, 09:26 PM
posted to microsoft.public.access.reports
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How to total my DateDiff Field in a report
Thank you, right after sending this message I caught the error!
"Marshall Barton" wrote: "Marcy@airproducts" wrote: In my report I need to total my DateDiff field (=DateDiff("d",[Date Rejected],[Date Completed]) in the header. It is a number of days, but when I try =Sum([DateDiff("d",[Date Rejected],[Date Completed])]) the expression is too complicated. How can I get my report to total all the days? There is an extra ] in that expression. Also make sure that [Date Rejected] and [Date Completed] are **fields** in the report's record source table/query and not controls on the report. -- Marsh MVP [MS Access]
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