date criteria to select range

Mail enroute.

Unsure if it is possible.

Thanks

Kristan


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ugh!

g

Biff

"Max" wrote in message
...
Believe essentially that you have dates running along from B1 across (B1,
C1, D1, ...) which do not necessarily start from the 1st of the month in
B1

Try this revision:

=IF(S17=0,0,IF(AND(DAY(TODAY())=1,DAY(TODAY())=6 ),SUMPRODUCT((OFFSET(A9,,M
ATCH(TODAY(),$1:$1,0)-1,,-(MATCH(TODAY(),$1:$1,0)-MATCH(DATE(YEAR(TODAY()),M
ONTH(TODAY()),1),$1:$1,0)+1))),(OFFSET(A17,,MATCH( TODAY(),$1:$1,0)-1,,-(MATC
H(TODAY(),$1:$1,0)-MATCH(DATE(YEAR(TODAY()),MONTH(TODAY()),1),$1:$1,0 )+1))))
/S17,SUMPRODUCT((OFFSET(A9,,MATCH(TODAY(),$1:$1,0)-1,,-7)),(OFFSET(A17,,MATC
H(TODAY(),$1:$1,0)-1,,-7)))/S17))

The changes made are to the 2nd IF whe

IF(AND(DAY(TODAY())=1,DAY(TODAY())=6)

replaces the previous :

IF(MATCH(TODAY(),$1:$1,0)-17

and to the width params of OFFSET within the 1st SUMPRODUCT, whe

-(MATCH(TODAY(),$1:$1,0)-MATCH(DATE(YEAR(TODAY()),MONTH(TODAY()),1),$1:$1,0 )
+1

replaces the previous:

-(MATCH(TODAY(),$1:$1,0)-1

--
Rgds
Max
xl 97
---
Singapore, GMT+8
xdemechanik
http://savefile.com/projects/236895
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"Kstalker" wrote
in
message ...

Alternatively.... Is it possible to add criteria to the equation below.

The reason I ask is I am trying to stop the equation below (which works
perfectly thanks Max) from going past the 1st of the month should i be
trying to add a weekly summary from the 6th day of the month back to
the 1st.

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 .......etc
(--------------)


"=IF(S17=0,0,IF(MATCH(TODAY(),$1:$1,0)-17,SUMPRODUCT((OFFSET(A9,,MATCH(TODA
Y(),$1:$1,0)-1,,-(MATCH(TODAY(),$1:$1,0)-1))),(OFFSET(A17,,MATCH(TODAY(),$1:
$1,0)-1,,-(MATCH(TODAY(),$1:$1,0)-1))))/S17,SUMPRODUCT((OFFSET(A9,,MATCH(TOD
AY(),$1:$1,0)-1,,-7)),(OFFSET(A17,,MATCH(TODAY(),$1:$1,0)-1,,-7)))/S17))"

All help greatly appreciated


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"Kstalker" wrote:
Mail enroute.
Unsure if it is possible.

Thanks for alert. I can only access my yahoo acc in about 10 hours time, so
hang in there awhile. I will post back the findings either way g.

In the interim ... FWIW I had actually prepared a response (below) to your
earlier post yesterday on the new issue raised before your 2nd post came
through. In case you would like to see it through:

The formula below is being used to sumproduct any data where the
criteria "stop" is met. However I can only sum this data (sumif) which
is not accurate as if more than one coumn contains the criteria it is
summed . Is there a way that I can set the criteria as in using the
sumif function but still produce the sumproduct results??

=IF(S30=0,0,SUMPRODUCT(SUMIF($A$2:$Q$2,"stop",A19: Q19),SUMIF($A$2:$Q$2,"stop
",A30:Q30)/S30))

Think I might have lost my way somewhere here ..

As it stands, your posted formula is equivalent to:

=IF(S30=0,0,SUMIF($A$2:$Q$2,"stop",A19:Q19)*SUMIF( $A$2:$Q$2,"stop",A30:Q30)/
S30)

(i.e. with the "*" replacing the SUMPRODUCT( ..))

So, supposing you have:

In A2:C2: stop stop stop
In A19:C19: 10 10 10
In A30:C30: 100 100 100
In S30: 2

(All other cells within the posted formula are assumed blank)

Your posted formula will return: 4500 (nothing wrong here), viz.:

SUMIF($A$2:$Q$2,"stop",A19:Q19) returns: 30
SUMIF($A$2:$Q$2,"stop",A30:Q30)/S30 returns: 150
and then SUMPRODUCT(30,150) will return: 30 x 150 = 4500

What is your expected result ?
If it's another value, pl explain how the expected result is computed

And if we clear say, cell C2, so that it becomes

In A2:C2: stop stop blank
In A19:C19: 10 10 10
In A30:C30: 100 100 100
In S30: 2

Your posted formula will return: 2000 (again, nothing wrong here)
What is your expected result ?
If it's another value, pl explain how the expected result is computed

--
Rgds
Max
xl 97
---
Singapore, GMT+8
xdemechanik
http://savefile.com/projects/236895
---

"Biff" wrote
ugh!
g

Thanks ! g
--
Rgds
Max
xl 97
---
Singapore, GMT+8
xdemechanik
http://savefile.com/projects/236895
---

Kristan,

Ok, I've had a few really close looks and re-tested it
several times, but I couldn't find anything wrong with
the latest formula which was suggested. The formula
doesn't pick up what's to the left of the 1st day of
the month.

Please refer to the attached file*, where I've
simulated the test in the sheet: Begining month

In K14 is the same formula as in K11
but with "TODAY()" replaced by: "DATE(2005,8,4)" to
simulate as if "today" is 4th Aug 2005. You'll see
that the correct result is returned in K14 (same
answer as your K9).

*File: Kristan2a_Example.xls
http://savefile.com/files/8213621

--
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Max
xl 97
---
Singapore, GMT+8
xdemechanik
http://savefile.com/projects/236895
--

Max.

Works perfectly. An error on my behalf prevented the reply you posted a
few back from working so appologies for using up more of your time and
not using the formula correctly.

Yet again there has been a wealth of useful information on and provided
through this site, I regularly recommend it to others.

Thanks again for your input Max.

Regards

Kristan


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You're welcome, Kristan !
Glad it finally worked out ok for you ..
--
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Max
xl 97
---
Singapore, GMT+8
xdemechanik
http://savefile.com/projects/236895
--

No problem with all the attached solutions to this thread but have an
enhancement that needs to be made and was wondering how to acheive
this.

Instead of running from todays date I need to run from yesterdays date.
If anybody has the patience could you advise on how i reconfigure the
today component of:

=IF(S17=0,0,IF(AND(DAY(TODAY())=1,DAY(TODAY())=6 ),SUMPRODUCT((OFFSET(A9,,MATCH(TODAY(),$1:$1,0)-1,,-(MATCH(TODAY(),$1:$1,0)-MATCH(DATE(YEAR(TODAY()),MONTH(TODAY()),1),$1:$1,0 )+1))),(OFFSET(A17,,MATCH(
TODAY(),$1:$1,0)-1,,-(MATCH(TODAY(),$1:$1,0)-MATCH(DATE(YEAR(TODAY()),MONTH(TODAY()),1),$1:$1,0
)+1))))/S17,SUMPRODUCT((OFFSET(A9,,MATCH(TODAY(),$1:$1,0)-1,,-7)),(OFFSET(A17,,MATCH(TODAY(),$1:$1,0)-1,,-7)))/S17))


to search on yesterdays date instead?

I am certain it is simple but cannot crack it.

Thanks in advance

Kristan


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... to search on yesterdays date instead?

Think we just need to do an Edit Replace on the
cell with the posted working formula

Find what: TODAY()
Replace with: TODAY()-1

which yields:

=IF(S17=0,0,IF(AND(DAY(TODAY()-1)=1,DAY(TODAY()-1)=6),SUMPRODUCT((OFFSET(A
9,,MATCH(TODAY()-1,$1:$1,0)-1,,-(MATCH(TODAY()-1,$1:$1,0)-MATCH(DATE(YEAR(TO
DAY()-1),MONTH(TODAY()-1),1),$1:$1,0 )+1))),(OFFSET(A17,,MATCH(
TODAY()-1,$1:$1,0)-1,,-(MATCH(TODAY()-1,$1:$1,0)-MATCH(DATE(YEAR(TODAY()-1),
MONTH(TODAY()-1),1),$1:$1,0 )+1))))/S17,SUMPRODUCT((OFFSET(A9,,MATCH(TODAY()
-1,$1:$1,0)-1,,-7)),(OFFSET(A17,,MATCH(TODAY()-1,$1:$1,0)-1,,-7)))/S17))

(Above lightly tested in order g)

--
Rgds
Max
xl 97
---
Singapore, GMT+8
xdemechanik
http://savefile.com/projects/236895
--
"Kstalker" wrote in
message ...

No problem with all the attached solutions to this thread but have an
enhancement that needs to be made and was wondering how to acheive
this.

Instead of running from todays date I need to run from yesterdays date.
If anybody has the patience could you advise on how i reconfigure the
today component of:


=IF(S17=0,0,IF(AND(DAY(TODAY())=1,DAY(TODAY())=6 ),SUMPRODUCT((OFFSET(A9,,M
ATCH(TODAY(),$1:$1,0)-1,,-(MATCH(TODAY(),$1:$1,0)-MATCH(DATE(YEAR(TODAY()),M
ONTH(TODAY()),1),$1:$1,0)+1))),(OFFSET(A17,,MATCH(

TODAY(),$1:$1,0)-1,,-(MATCH(TODAY(),$1:$1,0)-MATCH(DATE(YEAR(TODAY()),MONTH(
TODAY()),1),$1:$1,0
)+1))))/S17,SUMPRODUCT((OFFSET(A9,,MATCH(TODAY(),$1:$1,0)-1,,-7)),(OFFSET(
A17,,MATCH(TODAY(),$1:$1,0)-1,,-7)))/S17))


to search on yesterdays date instead?

I am certain it is simple but cannot crack it.

Thanks in advance

Kristan


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Cheers Max.

I though it was as simple as that but I keep coming up with a 'false'
result using the formula below.....

=IF(AND(DAY(TODAY()-1)=1,DAY(TODAY()-1)=6),AVERAGE(OFFSET(A536,,MATCH(TODAY()-1,$338:$338,0)-1,,-(MATCH(TODAY()-1,$338:$338,0)-MATCH(DATE(YEAR(TODAY()-1),MONTH(TODAY()-1),1),19:19,0)+1))))

Absoultely stumped.....


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