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#1
December 14th, 2006, 09:59 PM
posted to microsoft.public.access.forms
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Check Box properties
I need to make a check box visible/invisible according to a user
selection from another combo box. I have used this in the past, CheckName of checkbox.visible = false and on running a database that I created about three years ago this works fine. However implementing the same thing in a new database I am constructing gives a 'Run Time Error '424' Object required, using the same syntax. Labels I am using work correctly with labelName of label.visible = false, its just check boxes I am having a problem with. I am now using Access2002 (10.6771.6817)SP3 and Win XP Pro The other database was constructed in Access 2000 and Win2000 Pro but it runs and performs correctly on the new system. I am only getting this error in the new database. Thanks in anticipation regards Mike 
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#2
December 14th, 2006, 10:05 PM
posted to microsoft.public.access.forms
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Check Box properties
Can you give an example of exactly what you mean by "CheckName of
checkbox"? -- Doug Steele, Microsoft Access MVP http://I.Am/DougSteele (no private e-mails, please) "Mike" wrote in message . uk... I need to make a check box visible/invisible according to a user selection from another combo box. I have used this in the past, CheckName of checkbox.visible = false and on running a database that I created about three years ago this works fine. However implementing the same thing in a new database I am constructing gives a 'Run Time Error '424' Object required, using the same syntax. Labels I am using work correctly with labelName of label.visible = false, its just check boxes I am having a problem with. I am now using Access2002 (10.6771.6817)SP3 and Win XP Pro The other database was constructed in Access 2000 and Win2000 Pro but it runs and performs correctly on the new system. I am only getting this error in the new database. Thanks in anticipation regards Mike
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#3
December 14th, 2006, 10:12 PM
posted to microsoft.public.access.forms
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Check Box properties
You don't use the word Check or Label in your statement.
Always qualify the control with the name of the form or if you are working within the current form, you can use either Me. or Me! Me.chkAnyName.Visible = False "Mike" wrote: I need to make a check box visible/invisible according to a user selection from another combo box. I have used this in the past, CheckName of checkbox.visible = false and on running a database that I created about three years ago this works fine. However implementing the same thing in a new database I am constructing gives a 'Run Time Error '424' Object required, using the same syntax. Labels I am using work correctly with labelName of label.visible = false, its just check boxes I am having a problem with. I am now using Access2002 (10.6771.6817)SP3 and Win XP Pro The other database was constructed in Access 2000 and Win2000 Pro but it runs and performs correctly on the new system. I am only getting this error in the new database. Thanks in anticipation regards Mike
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#4
December 15th, 2006, 07:45 PM
posted to microsoft.public.access.forms
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Check Box properties
Klatuu wrote:
You don't use the word Check or Label in your statement. Always qualify the control with the name of the form or if you are working within the current form, you can use either Me. or Me! Me.chkAnyName.Visible = False "Mike" wrote: I need to make a check box visible/invisible according to a user selection from another combo box. I have used this in the past, CheckName of checkbox.visible = false and on running a database that I created about three years ago this works fine. However implementing the same thing in a new database I am constructing gives a 'Run Time Error '424' Object required, using the same syntax. Labels I am using work correctly with labelName of label.visible = false, its just check boxes I am having a problem with. I am now using Access2002 (10.6771.6817)SP3 and Win XP Pro The other database was constructed in Access 2000 and Win2000 Pro but it runs and performs correctly on the new system. I am only getting this error in the new database. Thanks in anticipation regards Mike Thanks Klatuu It worked OK when I just used the name of the checkbox and I wonder why this has not come up before as I did not have any problems before using the check[checkboxname] format. I have not used Me. or Me! I am working within the current form so is it important to always qualify the control in this way?
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#5
December 15th, 2006, 08:14 PM
posted to microsoft.public.access.forms
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Check Box properties
Although, as you have seen, you can get away with it in most cases, it is a
really good idea to qualify the references so there will be no confusion. "Mike" wrote: Klatuu wrote: You don't use the word Check or Label in your statement. Always qualify the control with the name of the form or if you are working within the current form, you can use either Me. or Me! Me.chkAnyName.Visible = False "Mike" wrote: I need to make a check box visible/invisible according to a user selection from another combo box. I have used this in the past, CheckName of checkbox.visible = false and on running a database that I created about three years ago this works fine. However implementing the same thing in a new database I am constructing gives a 'Run Time Error '424' Object required, using the same syntax. Labels I am using work correctly with labelName of label.visible = false, its just check boxes I am having a problem with. I am now using Access2002 (10.6771.6817)SP3 and Win XP Pro The other database was constructed in Access 2000 and Win2000 Pro but it runs and performs correctly on the new system. I am only getting this error in the new database. Thanks in anticipation regards Mike Thanks Klatuu It worked OK when I just used the name of the checkbox and I wonder why this has not come up before as I did not have any problems before using the check[checkboxname] format. I have not used Me. or Me! I am working within the current form so is it important to always qualify the control in this way?
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