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#1
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Sum and DateDiff
Hi,
I doing a calculation in a query of the difference in times. I'm wondering if I can control the decimal precision to be just (2) places. The number I end up with is ie; 5.6666666666, can I have this to round off to something like 5.67? Here is the query expression I'm using for this; TotalTime: Sum(DateDiff("n",[StartTime],[EndTime])/60) Thanks you, |
#2
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Sum and DateDiff
On Sat, 5 Jun 2010 19:33:30 -0700, Kelly
wrote: Hi, I doing a calculation in a query of the difference in times. I'm wondering if I can control the decimal precision to be just (2) places. The number I end up with is ie; 5.6666666666, can I have this to round off to something like 5.67? Here is the query expression I'm using for this; TotalTime: Sum(DateDiff("n",[StartTime],[EndTime])/60) Thanks you, Su TotalTime: Round(Sum(DateDiff("n",[StartTime],[EndTime])/60),2) -- John W. Vinson [MVP] |
#3
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Sum and DateDiff
That worked perfect! Thank You
"John W. Vinson" wrote: On Sat, 5 Jun 2010 19:33:30 -0700, Kelly wrote: Hi, I doing a calculation in a query of the difference in times. I'm wondering if I can control the decimal precision to be just (2) places. The number I end up with is ie; 5.6666666666, can I have this to round off to something like 5.67? Here is the query expression I'm using for this; TotalTime: Sum(DateDiff("n",[StartTime],[EndTime])/60) Thanks you, Su TotalTime: Round(Sum(DateDiff("n",[StartTime],[EndTime])/60),2) -- John W. Vinson [MVP] . |
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