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#DIV/0! ERROR



 
 
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  #1  
Old January 17th, 2010, 09:41 PM posted to microsoft.public.excel.worksheet.functions
dbconn
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Posts: 16
Default #DIV/0! ERROR

I have a worksheet that has a number of rows in each of several different
categories. Before any information is entered, each row shows a 0 sum. When
information is entered in the first cell of a given row, a new sum is entered
for that row based on the formulas in the rows. In each category, the sums
column computes an average. I have that formula working so that it disegards
any 0's, but until the first cell in at least one row has something entered,
the average cell shows "#DIV/0!". I need to compute a master average of these
individual averages, but not all catgories will have information. My master
average shows #DIV/0! if any of the individual averages show the error. Any
ideas?
--
dbconn
  #2  
Old January 17th, 2010, 10:05 PM posted to microsoft.public.excel.worksheet.functions
Gary''s Student
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Posts: 7,584
Default #DIV/0! ERROR

=IF(ISERROR(yourformula),"",yourformula)
--
Gary''s Student - gsnu200909
  #3  
Old January 18th, 2010, 08:39 PM posted to microsoft.public.excel.worksheet.functions
Gord Dibben
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Posts: 20,252
Default #DIV/0! ERROR

Get rid of the 0 sums until data entered.

=IF(COUNT(A1:C1)2,"",SUM(A1:C1))

Your Average formula will ignore ""


Gord Dibben MS Excel MVP

On Sun, 17 Jan 2010 13:41:01 -0800, dbconn
wrote:

I have a worksheet that has a number of rows in each of several different
categories. Before any information is entered, each row shows a 0 sum. When
information is entered in the first cell of a given row, a new sum is entered
for that row based on the formulas in the rows. In each category, the sums
column computes an average. I have that formula working so that it disegards
any 0's, but until the first cell in at least one row has something entered,
the average cell shows "#DIV/0!". I need to compute a master average of these
individual averages, but not all catgories will have information. My master
average shows #DIV/0! if any of the individual averages show the error. Any
ideas?


 




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