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#1
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find unique records
How do i search a column of data which contains for instance multiple numbers
of headings, find each unique record item (ie apple , pear, orange) and then display a list of each type (no duplicates) in a new range of cells. I will then be able to use this record list as a means of providing a "record type count" in a different worksheet. Thanks |
#2
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find unique records
Thanks Jacob, but i am after is firt of all a list of the unique record items
so that i can then do a count seperately using that list asthe basis of the count formula. Cheers "Jacob Skaria" wrote: You can get the count of unique items using the below formula.. =SUMPRODUCT((A2:A100"")/COUNTIF(A2:A100,A2:A100&"")) If this post helps click Yes --------------- Jacob Skaria "frankfurtjoe" wrote: How do i search a column of data which contains for instance multiple numbers of headings, find each unique record item (ie apple , pear, orange) and then display a list of each type (no duplicates) in a new range of cells. I will then be able to use this record list as a means of providing a "record type count" in a different worksheet. Thanks |
#3
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find unique records
You can get the count of unique items using the below formula..
=SUMPRODUCT((A2:A100"")/COUNTIF(A2:A100,A2:A100&"")) If this post helps click Yes --------------- Jacob Skaria "frankfurtjoe" wrote: How do i search a column of data which contains for instance multiple numbers of headings, find each unique record item (ie apple , pear, orange) and then display a list of each type (no duplicates) in a new range of cells. I will then be able to use this record list as a means of providing a "record type count" in a different worksheet. Thanks |
#4
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find unique records
Say your original datalist is in A1 to A200.
In B1 enter: =A1 In B2, enter this *array* formula: =IF(ISERR(MATCH(0,COUNTIF(B$1:B1,$A$1:$A$200&""),0 )),"",INDEX(IF(ISBLANK($A$1:$A$200),"",$A$1:$A$200 ),MATCH(0,COUNTIF(B$1:B1,$A$1:$A$200&""),0))) -- Array formulas are entered using CSE, Ctrl Shift Enter, instead of the regular Enter, which will *automatically* enclose the formula in curly brackets, which *cannot* be done manually. Also, CSE *must* be used when revising the formula. *After* the array entry, copy down as needed. -- HTH, RD ================================================== === Please keep all correspondence within the Group, so all may benefit! ================================================== === "frankfurtjoe" wrote in message ... Thanks Jacob, but i am after is firt of all a list of the unique record items so that i can then do a count seperately using that list asthe basis of the count formula. Cheers "Jacob Skaria" wrote: You can get the count of unique items using the below formula.. =SUMPRODUCT((A2:A100"")/COUNTIF(A2:A100,A2:A100&"")) If this post helps click Yes --------------- Jacob Skaria "frankfurtjoe" wrote: How do i search a column of data which contains for instance multiple numbers of headings, find each unique record item (ie apple , pear, orange) and then display a list of each type (no duplicates) in a new range of cells. I will then be able to use this record list as a means of providing a "record type count" in a different worksheet. Thanks |
#5
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find unique records
Hello Frankfurtjoe: Assuming your data starts in row 2, paste this formula in cell C2 and copy down. Hide column C. Code: -------------------- =IF(A2="","",IF(COUNTIF(A$2:A2,A2)=1,COUNTIF(A$2:A $1000,""&A2)+ROW()/100000,"")) -------------------- Paste this formula in cell B2 and copy down. Code: -------------------- =IF(ISERROR(SMALL(C:C,ROW()-1)),"",INDEX(A$2:A$1000,MID(SMALL(C:C,ROW()-1),FIND(".",SMALL(C:C,ROW()-1)),6)*100000-1,1)) -------------------- This will list those unique items in alphabetical order without duplicates. -- GoBow777 |
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