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Horizontal lines per column on page



 
 
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  #1  
Old July 11th, 2007, 04:54 PM posted to microsoft.public.access.reports
jojo
external usenet poster
 
Posts: 83
Default Horizontal lines per column on page

Good day everyone,

Thanks again for making this site available.

I used the VBA from the post "Un-numbered horizontal lines" except took out
the Me.Print part of the code and it worked great. The problem I'm having
now is I am using the same code in a different report but instead of using it
in the detail section I am using it in a groupheader0 section (Date Header)
and the lines aren't showing up. I tried changing the intDetailHeight As
Integer to intgroupheader0 As Integer throughout the report. It was the only
thing I could think of to do. I just don't understand the principles of code
enough to fix the problem. Also, I need the line broken up - the left line
to start at the left margin and stop at about 3.58 and the right line should
start at 3.85 and go through the rest of the section.
Thanks for helping me!!!

--
MADBLover
  #2  
Old July 11th, 2007, 06:50 PM posted to microsoft.public.access.reports
jojo
external usenet poster
 
Posts: 83
Default Horizontal lines per column on page

Back again to be a little more clear - I used the horizontal line code in the
Reports On Page event and in the groupheaders On Print event to no avail.
Thought you might need to know that. Thanks!
--
MADBLover


"JoJo" wrote:

Good day everyone,

Thanks again for making this site available.

I used the VBA from the post "Un-numbered horizontal lines" except took out
the Me.Print part of the code and it worked great. The problem I'm having
now is I am using the same code in a different report but instead of using it
in the detail section I am using it in a groupheader0 section (Date Header)
and the lines aren't showing up. I tried changing the intDetailHeight As
Integer to intgroupheader0 As Integer throughout the report. It was the only
thing I could think of to do. I just don't understand the principles of code
enough to fix the problem. Also, I need the line broken up - the left line
to start at the left margin and stop at about 3.58 and the right line should
start at 3.85 and go through the rest of the section.
Thanks for helping me!!!

--
MADBLover

  #3  
Old July 11th, 2007, 07:00 PM posted to microsoft.public.access.reports
jojo
external usenet poster
 
Posts: 83
Default Horizontal lines per column on page

Okay, I figured out that I had to move the text boxes into the detail section
to get the horizontal lines - but I still would like to know how to get the
left line
to start at the left margin and stop at about 3.58 and the right line should
start at 3.85 and go through the rest of the section. Thanks for your help!!


--
MADBLover


"JoJo" wrote:

Good day everyone,

Thanks again for making this site available.

I used the VBA from the post "Un-numbered horizontal lines" except took out
the Me.Print part of the code and it worked great. The problem I'm having
now is I am using the same code in a different report but instead of using it
in the detail section I am using it in a groupheader0 section (Date Header)
and the lines aren't showing up. I tried changing the intDetailHeight As
Integer to intgroupheader0 As Integer throughout the report. It was the only
thing I could think of to do. I just don't understand the principles of code
enough to fix the problem. Also, I need the line broken up - the left line
to start at the left margin and stop at about 3.58 and the right line should
start at 3.85 and go through the rest of the section.
Thanks for helping me!!!

--
MADBLover

  #4  
Old July 11th, 2007, 07:52 PM posted to microsoft.public.access.reports
Marshall Barton
external usenet poster
 
Posts: 5,361
Default Horizontal lines per column on page

JoJo wrote:

Okay, I figured out that I had to move the text boxes into the detail section
to get the horizontal lines - but I still would like to know how to get the
left line
to start at the left margin and stop at about 3.58 and the right line should
start at 3.85 and go through the rest of the section.



We need more specific information. Under what conditions do
want which line to appear? Exactly what is the code that
you are using?

From what you've said so far, all I can say is that the Line
method (in the page event) would look like:

Me.Line (0, ???) - (3.85*1440, ???)

Where ??? should be the vertical distance (in twips) from
the top of the page.

Actually, at this point, I don't see why you can not use a
line control to do this.

--
Marsh
MVP [MS Access]
  #5  
Old July 11th, 2007, 09:16 PM posted to microsoft.public.access.reports
jojo
external usenet poster
 
Posts: 83
Default Horizontal lines per column on page

Sorry I didn't make myself clear, and I hope I make myself more clear this
time.
What I want is a two column report (already made) that has horizontal lines
that start at the left margin and stop at 3.58 and then start again at 3.85
and continue to the end of the right margin. The code below is what I'm
using in the OnPage event in the Reports section for Horizontal Lines. Hope
that's a little clearer. Thanks!

Dim intNumLines As Integer
Dim intLineNum As Integer
Dim intDetailHeight As Integer
Dim intPageHeadHeight As Integer
On Error GoTo Report_Page_Error

intNumLines = 14
intDetailHeight = Me.Section(acDetail).Height
intPageHeadHeight = Me.Section(3).Height
For intLineNum = 1 To intNumLines
Me.CurrentY = (intLineNum) * intDetailHeight + intPageHeadHeight
Me.CurrentX = 0
Me.Line (0, intPageHeadHeight + intLineNum * intDetailHeight)- _
Step(Me.Width, 3.5)
Next
On Error GoTo 0
Exit Sub

Report_Page_Error:
Select Case Err
Case 2462 'no page header
intPageHeadHeight = 0
Resume Next
End Select
MsgBox "Error" & Err.Number & "(" & Err.Description & _
")in procedure Report_Page of VBA Document Report_Report1"

--
MADBLover


"Marshall Barton" wrote:

JoJo wrote:

Okay, I figured out that I had to move the text boxes into the detail section
to get the horizontal lines - but I still would like to know how to get the
left line
to start at the left margin and stop at about 3.58 and the right line should
start at 3.85 and go through the rest of the section.



We need more specific information. Under what conditions do
want which line to appear? Exactly what is the code that
you are using?

From what you've said so far, all I can say is that the Line
method (in the page event) would look like:

Me.Line (0, ???) - (3.85*1440, ???)

Where ??? should be the vertical distance (in twips) from
the top of the page.

Actually, at this point, I don't see why you can not use a
line control to do this.

--
Marsh
MVP [MS Access]

  #6  
Old July 11th, 2007, 10:27 PM posted to microsoft.public.access.reports
Marshall Barton
external usenet poster
 
Posts: 5,361
Default Horizontal lines per column on page

JoJo wrote:

Sorry I didn't make myself clear, and I hope I make myself more clear this
time.
What I want is a two column report (already made) that has horizontal lines
that start at the left margin and stop at 3.58 and then start again at 3.85
and continue to the end of the right margin. The code below is what I'm
using in the OnPage event in the Reports section for Horizontal Lines. Hope
that's a little clearer. Thanks!

Dim intNumLines As Integer
Dim intLineNum As Integer
Dim intDetailHeight As Integer
Dim intPageHeadHeight As Integer
On Error GoTo Report_Page_Error

intNumLines = 14
intDetailHeight = Me.Section(acDetail).Height
intPageHeadHeight = Me.Section(3).Height
For intLineNum = 1 To intNumLines
Me.CurrentY = (intLineNum) * intDetailHeight + intPageHeadHeight
Me.CurrentX = 0
Me.Line (0, intPageHeadHeight + intLineNum * intDetailHeight)- _
Step(Me.Width, 3.5)
Next

[snip]

It looks like that code draws slanted lines all over the
page. Let's see if this does any better:

For intLineNum = 1 To intNumLines
Me.Line (0, intPageHeadHeight _
+ intLineNum * intDetailHeight)- _
Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, intPageHeadHeight _
+ intLineNum * intDetailHeight)- _
Step(3.58 * 1440, 0)
Next

--
Marsh
MVP [MS Access]
  #7  
Old July 12th, 2007, 03:46 PM posted to microsoft.public.access.reports
jojo
external usenet poster
 
Posts: 83
Default Horizontal lines per column on page

The code works great except can you make the lines start in the detail
section of the report instead of the top of the page? Also, the two columns
are for a payroll sheet. The left side of the column is suppose to have the
first week and the right side of the column the second but when I put the
columns setting to read across then down the dates show up like this
(1st column) (2nd column)
First Week Second Week
7/6/07 7/7/07
7/8/07 7/9/07
etc...
If I put the columns setting to read down then across all the dates end up
on the left side of the page. What I would like is this. (The dates are
text boxes)
(1st column) (2nd column)
First Week Second Week
7/9/07 7/16/07
7/10/07 7/17/07
7/11/07 7/18/07
7/12/07 7/19/07
7/13/07 7/20/07
Does what I'm saying make sense? Thanks so much for the help, it is
priceless!!!

--
MADBLover


"Marshall Barton" wrote:

JoJo wrote:

Sorry I didn't make myself clear, and I hope I make myself more clear this
time.
What I want is a two column report (already made) that has horizontal lines
that start at the left margin and stop at 3.58 and then start again at 3.85
and continue to the end of the right margin. The code below is what I'm
using in the OnPage event in the Reports section for Horizontal Lines. Hope
that's a little clearer. Thanks!

Dim intNumLines As Integer
Dim intLineNum As Integer
Dim intDetailHeight As Integer
Dim intPageHeadHeight As Integer
On Error GoTo Report_Page_Error

intNumLines = 14
intDetailHeight = Me.Section(acDetail).Height
intPageHeadHeight = Me.Section(3).Height
For intLineNum = 1 To intNumLines
Me.CurrentY = (intLineNum) * intDetailHeight + intPageHeadHeight
Me.CurrentX = 0
Me.Line (0, intPageHeadHeight + intLineNum * intDetailHeight)- _
Step(Me.Width, 3.5)
Next

[snip]

It looks like that code draws slanted lines all over the
page. Let's see if this does any better:

For intLineNum = 1 To intNumLines
Me.Line (0, intPageHeadHeight _
+ intLineNum * intDetailHeight)- _
Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, intPageHeadHeight _
+ intLineNum * intDetailHeight)- _
Step(3.58 * 1440, 0)
Next

--
Marsh
MVP [MS Access]

  #8  
Old July 12th, 2007, 06:58 PM posted to microsoft.public.access.reports
Marshall Barton
external usenet poster
 
Posts: 5,361
Default Horizontal lines per column on page

JoJo wrote:
The code works great except can you make the lines start in the detail
section of the report instead of the top of the page? Also, the two columns
are for a payroll sheet. The left side of the column is suppose to have the
first week and the right side of the column the second but when I put the
columns setting to read across then down the dates show up like this
(1st column) (2nd column)
First Week Second Week
7/6/07 7/7/07
7/8/07 7/9/07
etc...

If I put the columns setting to read down then across all the dates end up
on the left side of the page. What I would like is this. (The dates are
text boxes)
(1st column) (2nd column)
First Week Second Week
7/9/07 7/16/07
7/10/07 7/17/07
7/11/07 7/18/07
7/12/07 7/19/07
7/13/07 7/20/07



Ahhh, I think you might be running down the wrong road.

As long as this is not in a subreport, set the columns to
Down then Across.

You can get a line under/over each detail, just by adding a
line control at the bottom/top of the detail section.

Now, the subtle point is to use Sorting and Grouping (View
menu) to group on a week. Group on an expression like:
=DatePart("ww", thedatefield)
And set the group header section's NewRowOrCol property to
Before Section.

Use a text box in the group header to display the
column/group "label". For starters, just use an expression
like:
="Week " & DatePart("ww", thedatefield)

--
Marsh
MVP [MS Access]
  #9  
Old July 12th, 2007, 08:06 PM posted to microsoft.public.access.reports
jojo
external usenet poster
 
Posts: 83
Default Horizontal lines per column on page


--
MADBLover


"Marshall Barton" wrote:

JoJo wrote:
The code works great except can you make the lines start in the detail
section of the report instead of the top of the page? Also, the two columns
are for a payroll sheet. The left side of the column is suppose to have the
first week and the right side of the column the second but when I put the
columns setting to read across then down the dates show up like this
(1st column) (2nd column)
First Week Second Week
7/6/07 7/7/07
7/8/07 7/9/07
etc...

If I put the columns setting to read down then across all the dates end up
on the left side of the page. What I would like is this. (The dates are
text boxes)
(1st column) (2nd column)
First Week Second Week
7/9/07 7/16/07
7/10/07 7/17/07
7/11/07 7/18/07
7/12/07 7/19/07
7/13/07 7/20/07



Ahhh, I think you might be running down the wrong road.

As long as this is not in a subreport, set the columns to
Down then Across.

You can get a line under/over each detail, just by adding a
line control at the bottom/top of the detail section.

Now, the subtle point is to use Sorting and Grouping (View
menu) to group on a week. Group on an expression like:
=DatePart("ww", thedatefield)
And set the group header section's NewRowOrCol property to
Before Section.

Use a text box in the group header to display the
column/group "label". For starters, just use an expression
like:
="Week " & DatePart("ww", thedatefield)


Thanks Marsh for your help!!! It looks like the ="Week" & DatePart is just
what is needed. As far as the horizontal lines I need fourteen so just
drawing them above the field in the detail section will only give me lines
until the section runs out. Below is a concoction from examining what you
gave me and some other line methods, it seems to be working pretty
good(learning is an exciting adventure ☺!!) The thing is, you may have been
trying to tell me this all along but I am still learning and don't really
understand the code being given me until it is applied a few times. (P.S.
If the code below looks like too much and there's a shorter way, I don't
doubt there is, then please teach me some more!!! Thank you!!!)
Dim intNumLines As Integer
Dim intLineNum As Integer
Dim intDetailHeight As Integer
Dim intPageHeadHeight As Integer
On Error GoTo Report_Page_Error

intNumLines = 14
intDetailHeight = Me.Section(acDetail).Height
intPageHeadHeight = Me.Section(3).Height
For intLineNum = 1 To intNumLines
Me.Line (0 * 1440, 3700)-Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, 3700)-Step(3.85 * 1440, 0)
Me.Line (0 * 1440, 3950)-Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, 3950)-Step(3.85 * 1440, 0)
Me.Line (0 * 1440, 4200)-Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, 4200)-Step(3.85 * 1440, 0)
Me.Line (0 * 1440, 4450)-Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, 4450)-Step(3.85 * 1440, 0)
Me.Line (0 * 1440, 4685)-Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, 4685)-Step(3.85 * 1440, 0)
Me.Line (0 * 1440, 4930)-Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, 4930)-Step(3.85 * 1440, 0)
Me.Line (0 * 1440, 5165)-Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, 5165)-Step(3.85 * 1440, 0)
Next
On Error GoTo 0
Exit Sub

Report_Page_Error:
Select Case Err
Case 2462 'no page header
intPageHeadHeight = 0
Resume Next
End Select
MsgBox "Error" & Err.Number & "(" & Err.Description & _
")in procedure Report_Page of VBA Document Report_Report1"

--
Marsh
MVP [MS Access]

  #10  
Old July 12th, 2007, 08:59 PM posted to microsoft.public.access.reports
Marshall Barton
external usenet poster
 
Posts: 5,361
Default Horizontal lines per column on page

JoJo wrote:

Thanks Marsh for your help!!! It looks like the ="Week" & DatePart is just
what is needed. As far as the horizontal lines I need fourteen so just
drawing them above the field in the detail section will only give me lines
until the section runs out. Below is a concoction from examining what you
gave me and some other line methods, it seems to be working pretty
good(learning is an exciting adventure ?!!) The thing is, you may have been
trying to tell me this all along but I am still learning and don't really
understand the code being given me until it is applied a few times. (P.S.
If the code below looks like too much and there's a shorter way, I don't
doubt there is, then please teach me some more!!! Thank you!!!)
Dim intNumLines As Integer
Dim intLineNum As Integer
Dim intDetailHeight As Integer
Dim intPageHeadHeight As Integer
On Error GoTo Report_Page_Error

intNumLines = 14
intDetailHeight = Me.Section(acDetail).Height
intPageHeadHeight = Me.Section(3).Height
For intLineNum = 1 To intNumLines
Me.Line (0 * 1440, 3700)-Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, 3700)-Step(3.85 * 1440, 0)
Me.Line (0 * 1440, 3950)-Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, 3950)-Step(3.85 * 1440, 0)
Me.Line (0 * 1440, 4200)-Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, 4200)-Step(3.85 * 1440, 0)
Me.Line (0 * 1440, 4450)-Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, 4450)-Step(3.85 * 1440, 0)
Me.Line (0 * 1440, 4685)-Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, 4685)-Step(3.85 * 1440, 0)
Me.Line (0 * 1440, 4930)-Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, 4930)-Step(3.85 * 1440, 0)
Me.Line (0 * 1440, 5165)-Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, 5165)-Step(3.85 * 1440, 0)
Next



This should be close to a shorter version:

Dim intNumLines As Integer
Dim intLineNum As Integer
Dim intDetailHeight As Integer
Dim intPageHeadHeight As Integer
Dim lng1stDetail As Long
Dim lngVPos As Long
On Error GoTo Report_Page_Error

intNumLines = 14
intDetailHeight = Me.Section(acDetail).Height
intPageHeadHeight = Me.Section(3).Height
lng1stDetail = 3700 ' intDetailHeight + intPageHeadHeight
For intLineNum = 0 To intNumLines - 1
lngVPos = lng1stDetail + intLineNum * intDetailHeight
Me.Line (0 * 1440, lngVPos)-Step(3.58 * 1440, 0)
Me.Line (3.85 * 1440, lngVPos)-Step(3.58 * 1440, 0)
Next


--
Marsh
MVP [MS Access]
 




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