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#1
January 8th, 2007, 11:00 PM
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Trying to find a single quote (') within text
We are using an application called MRI on top of MS SQL 2000 database. I am
trying to find a quote character within a text field using like '%'%', but get the following error message "Error -241721908: 0: Command text was not set for the command object. (proc: rdoExecSql  ". How do I find a single quote in a text field using like? Ken 
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#2
January 8th, 2007, 11:29 PM
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Trying to find a single quote (') within text
I assume you use 2 single quotes within single quotes
LIKE '%''%' "Ken King"wrote: We are using an application called MRI on top of MS SQL 2000 database. I am trying to find a quote character within a text field using like '%'%', but get the following error message "Error -241721908: 0: Command text was not set for the command object. (proc: rdoExecSql ". How do I find a singlequote in a text field using like? Ken
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#3
January 9th, 2007, 02:13 AM
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Trying to find a single quote (') within text
Ken King wrote:
We are using an application called MRI on top of MS SQL 2000 database. I am trying to find a quote character within a text field using like '%'%', but get the following error message "Error -241721908: 0: Command text was not set for the command object. (proc: rdoExecSql ". How do I find a single quote in a text field using like? Ken Look for CHR(39) (if that's an option). -- Smartin
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#4
January 9th, 2007, 10:51 AM
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Trying to find a single quote (') within text
USE pubs
GO SELECT au_lname FROM authors WHERE au_lname LIKE '%''%' ORDER by au_lname GO returns O'Leary "Gary Walter" wrote: I assume you use 2 single quotes within single quotes LIKE '%''%' "Ken King"wrote: We are using an application called MRI on top of MS SQL 2000 database. I am trying to find a quote character within a text field using like '%'%', but get the following error message "Error -241721908: 0: Command text was not set for the command object. (proc: rdoExecSql ". How do I find a singlequote in a text field using like? Ken
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