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Rounding Time
The function is designed to cater for any numeric data type, not just
date/time values, which is why its arguments are declared as Double. In your case it just so happens that you dealing with date/time values, so it make sense to declare the variable for the value to be passed to the function as Date. A date/time value is implemented as a 64 bit floating point number in fact; we just normally see it in a date/time format. In the original thread in which I posted this function there was subsequent input from David Fenton, who made pertinent points about the advisability of breaking the expression down and assigning the result of each constituent operation to its own variable to avoid rounding errors. This lead to the amendment of the function to: Public Function RoundToInterval(dblVal As Double, _ dblTo As Double, _ Optional blnUp As Boolean = True) As Double ' rounds up by default. ' to round down pass False into function as ' optional UpDown argument Dim intUpDown As Integer Dim lngTestValue As Long Dim dblTestValue As Double Dim dblDenominator As Double If blnUp Then intUpDown = -1 Else intUpDown = 1 End If dblDenominator = intUpDown * dblTo dblTestValue = dblVal / dblDenominator lngTestValue = Int(dblTestValue) RoundToInterval = intUpDown * lngTestValue * dblTo End Function It would be called in the same way, e.g. to round up, which is the default: CDate(RoundToInterval(#8:14:59#,#00:15:00#)) or to round down: CDate(RoundToInterval(#8:14:59#,#00:15:00#,False)) Ken Sheridan Stafford, England Bre-x wrote: Hi You are declaring the dTime as a Date Variable the first variable that the RoundTo Function is expecting is a Double I am missing something here? Literal example CDate(Roundto(#8:14:59#,#00:15:00#)) [quoted text clipped - 3 lines] dTime = #8:14:59# CDate(Roundto(dTime,#00:15:00#)) Public Function RoundTo(dblVal As Double _ , dblTo As Double _ , Optional intUpDown As Integer = -1) As Double ' rounds up by default. ' to round down pass 1 into function as ' optional intUpDown argument. RoundTo = intUpDown * (Int(dblVal / (intUpDown * dblTo))) * dblTo -- Message posted via AccessMonster.com http://www.accessmonster.com/Uwe/For...arted/201005/1 |
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