|
| If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. |
|
|||||||
|
|
Thread Tools | Display Modes |
|
#1
June 24th, 2009, 12:36 AM
posted to microsoft.public.excel.worksheet.functions
|
|||
|
|||
@IF Formula
Hello, I struggle incorporating @IF formulas.
I have three date columns. I need to find the work days between any two dates. My challenge is when I use the following formula for the following dates: K5 reflects 01/09/2009 and J5 reflects 01/09/2009 and I5 reflects 01/02/2009 I use the formula =NETWORKDAYS(J5,K5) the value comes to 1 and it should be zero. I use the formula =NETWORKDAYS(I5,K5) the value comes to 6 and should be 5 Also another challenge I can't figure out: K6 reflects 01/12/2009 and J5 reflects 01/13/2009 I use the formula =NETWORKDAYS(I5,K5) the value comes to (2) and should be (1). Thank you in advance for your help!! 
|
|
#2
June 24th, 2009, 01:09 AM
posted to microsoft.public.excel.worksheet.functions
|
|||
|
|||
|
@IF Formula
The range of dates 01/12/2009 and 01/13/2009 contains two work days when one
counts inclusively If you want an exclusive count use =NETWORKDAYS(I5,K5) -1 best wishes -- Bernard V Liengme Microsoft Excel MVP http://people.stfx.ca/bliengme remove caps from email "Ann 'Formula challenged'" Ann 'Formula challenged' @discussions.microsoft.com wrote in message ... Hello, I struggle incorporating @IF formulas. I have three date columns. I need to find the work days between any two dates. My challenge is when I use the following formula for the following dates: K5 reflects 01/09/2009 and J5 reflects 01/09/2009 and I5 reflects 01/02/2009 I use the formula =NETWORKDAYS(J5,K5) the value comes to 1 and it should be zero. I use the formula =NETWORKDAYS(I5,K5) the value comes to 6 and should be 5 Also another challenge I can't figure out: K6 reflects 01/12/2009 and J5 reflects 01/13/2009 I use the formula =NETWORKDAYS(I5,K5) the value comes to (2) and should be (1). Thank you in advance for your help!!
|
|
#3
June 24th, 2009, 05:40 PM
posted to microsoft.public.excel.worksheet.functions
|
|||
|
|||
|
@IF Formula
Hi,
I actually need an @IF function incorporated as it doesn't work when it is a negative number such as my example. Would you be able to incorproate an @IF into my NETWORDDAYS formula? I can't seem to get the right brackets or signs to get it to be valid. So it should be something like if K5=orJK than +1, if K5=or1, than -1 "Bernard Liengme" wrote: The range of dates 01/12/2009 and 01/13/2009 contains two work days when one counts inclusively If you want an exclusive count use =NETWORKDAYS(I5,K5) -1 best wishes -- Bernard V Liengme Microsoft Excel MVP http://people.stfx.ca/bliengme remove caps from email "Ann 'Formula challenged'" Ann 'Formula challenged' @discussions.microsoft.com wrote in message ... Hello, I struggle incorporating @IF formulas. I have three date columns. I need to find the work days between any two dates. My challenge is when I use the following formula for the following dates: K5 reflects 01/09/2009 and J5 reflects 01/09/2009 and I5 reflects 01/02/2009 I use the formula =NETWORKDAYS(J5,K5) the value comes to 1 and it should be zero. I use the formula =NETWORKDAYS(I5,K5) the value comes to 6 and should be 5 Also another challenge I can't figure out: K6 reflects 01/12/2009 and J5 reflects 01/13/2009 I use the formula =NETWORKDAYS(I5,K5) the value comes to (2) and should be (1). Thank you in advance for your help!!
|
|
#4
June 24th, 2009, 08:00 PM
posted to microsoft.public.excel.worksheet.functions
|
|||
|
|||
|
@IF Formula
=ABS(NETWORKDAYS(I5,K5))
will always give a positive value =IF(K5=I5,NETWORKDAYS(I5,K5),"") will give answer when K5 ==I5 but will return blank otherwise best wishes -- Bernard V Liengme Microsoft Excel MVP http://people.stfx.ca/bliengme remove caps from email "Ann ''Formula challenged''" wrote in message ... Hi, I actually need an @IF function incorporated as it doesn't work when it is a negative number such as my example. Would you be able to incorproate an @IF into my NETWORDDAYS formula? I can't seem to get the right brackets or signs to get it to be valid. So it should be something like if K5=orJK than +1, if K5=or1, than -1 "Bernard Liengme" wrote: The range of dates 01/12/2009 and 01/13/2009 contains two work days when one counts inclusively If you want an exclusive count use =NETWORKDAYS(I5,K5) -1 best wishes -- Bernard V Liengme Microsoft Excel MVP http://people.stfx.ca/bliengme remove caps from email "Ann 'Formula challenged'" Ann 'Formula challenged' @discussions.microsoft.com wrote in message ... Hello, I struggle incorporating @IF formulas. I have three date columns. I need to find the work days between any two dates. My challenge is when I use the following formula for the following dates: K5 reflects 01/09/2009 and J5 reflects 01/09/2009 and I5 reflects 01/02/2009 I use the formula =NETWORKDAYS(J5,K5) the value comes to 1 and it should be zero. I use the formula =NETWORKDAYS(I5,K5) the value comes to 6 and should be 5 Also another challenge I can't figure out: K6 reflects 01/12/2009 and J5 reflects 01/13/2009 I use the formula =NETWORKDAYS(I5,K5) the value comes to (2) and should be (1). Thank you in advance for your help!!
|
| Thread Tools | |
| Display Modes | |
|
|
Linear Mode
