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#1
February 15th, 2006, 08:30 PM
posted to microsoft.public.access.gettingstarted
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Julian Dates
Is there a way within an access database to change Julian Dates into regular
dates? Any help would be greatly appreciated 
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#2
February 15th, 2006, 09:17 PM
posted to microsoft.public.access.gettingstarted
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Julian Dates
On Wed, 15 Feb 2006 15:30:35 -0500, "Chris"
wrote: Is there a way within an access database to change Julian Dates into regular dates? Any help would be greatly appreciated Yes, but... The term "Julian Date" is used for a vast variety of different date formats (the Astronomical JD, Modified Astronomical JD, yyyyddd format, yyddd format, the bizarre military Julian Date with just one digit for the year, etc.) Which particular flavor of Julian Date did you have in mind? John W. Vinson[MVP]
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#3
February 15th, 2006, 09:32 PM
posted to microsoft.public.access.gettingstarted
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Julian Dates
06046 being February 25, 2006.. first two digits being year next three
being the numbered day of the year "John Vinson" wrote in message ... On Wed, 15 Feb 2006 15:30:35 -0500, "Chris" wrote: Is there a way within an access database to change Julian Dates into regular dates? Any help would be greatly appreciated Yes, but... The term "Julian Date" is used for a vast variety of different date formats (the Astronomical JD, Modified Astronomical JD, yyyyddd format, yyddd format, the bizarre military Julian Date with just one digit for the year, etc.) Which particular flavor of Julian Date did you have in mind? John W. Vinson[MVP]
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#4
February 15th, 2006, 10:50 PM
posted to microsoft.public.access.gettingstarted
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Julian Dates
"Chris" wrote in message
... 06046 being February 25, 2006.. first two digits being year next three being the numbered day of the year Is that a numeric field, or a text one? For numeric: Function ConvertJulian(JulianDate As Long) As Date ConvertJulian = DateSerial ( _ 2000 + (JulianDate \ 1000), _ 1, _ JulianDate Mod 1000) End Function For text: Function ConvertJulian(JulianDate As String) As Date ConvertJulian = DateSerial( _ 2000 + CLng(Left(JulianDate, 2)), _ 1, _ CLng(Mid(JulianDate, 3, 3))) End Function -- Doug Steele, Microsoft Access MVP http://I.Am/DougSteele (no private e-mails, please)
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