If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. |
|
|
Thread Tools | Display Modes |
#1
|
|||
|
|||
Satisfying two conditions?
I need to satisfy the following condition: If the longest side of a box is
greater than 60 or its second longest side is greater than 30, then charge $8. I have the Length, Width and Height measurements of each package in columns A,B, C. Example ABC 59,35,15 Thanks in advance for the help. Regards, ZUO |
#2
|
|||
|
|||
Satisfying two conditions?
For entries on row 2:
=IF(OR(A260,B230),8,1) Ok, you may want a different number than 1 for the other cost, but I'm trying to attract customers for you. "Zuo" wrote: I need to satisfy the following condition: If the longest side of a box is greater than 60 or its second longest side is greater than 30, then charge $8. I have the Length, Width and Height measurements of each package in columns A,B, C. Example ABC 59,35,15 Thanks in advance for the help. Regards, ZUO |
#3
|
|||
|
|||
Satisfying two conditions?
No, it must be if any of the numbers are greater than 60 or if the second
longest is greater than 30. You must take into account all numbers all the time. "JLatham" wrote: For entries on row 2: =IF(OR(A260,B230),8,1) Ok, you may want a different number than 1 for the other cost, but I'm trying to attract customers for you. "Zuo" wrote: I need to satisfy the following condition: If the longest side of a box is greater than 60 or its second longest side is greater than 30, then charge $8. I have the Length, Width and Height measurements of each package in columns A,B, C. Example ABC 59,35,15 Thanks in advance for the help. Regards, ZUO |
#4
|
|||
|
|||
Satisfying two conditions?
=IF(OR(MAX(A2:C2)60,LARGE(A2:C2,2)30),8,0)
Regards, Fred "Zuo" wrote in message news No, it must be if any of the numbers are greater than 60 or if the second longest is greater than 30. You must take into account all numbers all the time. "JLatham" wrote: For entries on row 2: =IF(OR(A260,B230),8,1) Ok, you may want a different number than 1 for the other cost, but I'm trying to attract customers for you. "Zuo" wrote: I need to satisfy the following condition: If the longest side of a box is greater than 60 or its second longest side is greater than 30, then charge $8. I have the Length, Width and Height measurements of each package in columns A,B, C. Example ABC 59,35,15 Thanks in advance for the help. Regards, ZUO |
#5
|
|||
|
|||
Satisfying two conditions?
You don't say what result you want if either condition is not met.
Try one of these... This one will return either 8 or 0: =(MAX(A2:C2)=30)*8 This one will return either 8 or blank: =IF(MAX(A2:C2)=30,8,"") -- Biff Microsoft Excel MVP "Zuo" wrote in message ... I need to satisfy the following condition: If the longest side of a box is greater than 60 or its second longest side is greater than 30, then charge $8. I have the Length, Width and Height measurements of each package in columns A,B, C. Example ABC 59,35,15 Thanks in advance for the help. Regards, ZUO |
#6
|
|||
|
|||
Satisfying two conditions?
=IF(MAX(A2:C2)30,8,"undefined")
"Zuo" wrote: No, it must be if any of the numbers are greater than 60 or if the second longest is greater than 30. You must take into account all numbers all the time. "JLatham" wrote: For entries on row 2: =IF(OR(A260,B230),8,1) Ok, you may want a different number than 1 for the other cost, but I'm trying to attract customers for you. "Zuo" wrote: I need to satisfy the following condition: If the longest side of a box is greater than 60 or its second longest side is greater than 30, then charge $8. I have the Length, Width and Height measurements of each package in columns A,B, C. Example ABC 59,35,15 Thanks in advance for the help. Regards, ZUO |
#7
|
|||
|
|||
Satisfying two conditions?
No, the problem is that I need to satisfy either of two conditions, first
condition is, are there any of the measurements longer than 60? A MAX formula resolves that easily. The problem then becomes is the second longest side (doesn't matter which), longer than 30? First you have to determine which is the second longest and then determine if it is longer than 30. That is why in my example I use a first measurement that is the longest but less than 60 and the second longest measurement which is more than 30. "Teethless mama" wrote: =IF(MAX(A2:C2)30,8,"undefined") "Zuo" wrote: No, it must be if any of the numbers are greater than 60 or if the second longest is greater than 30. You must take into account all numbers all the time. "JLatham" wrote: For entries on row 2: =IF(OR(A260,B230),8,1) Ok, you may want a different number than 1 for the other cost, but I'm trying to attract customers for you. "Zuo" wrote: I need to satisfy the following condition: If the longest side of a box is greater than 60 or its second longest side is greater than 30, then charge $8. I have the Length, Width and Height measurements of each package in columns A,B, C. Example ABC 59,35,15 Thanks in advance for the help. Regards, ZUO |
#8
|
|||
|
|||
Satisfying two conditions?
I have to give it to Fred Smith. That is what I needed, but thank you all
very much for trying to help. All your help is very much appreciated. "Fred Smith" wrote: =IF(OR(MAX(A2:C2)60,LARGE(A2:C2,2)30),8,0) Regards, Fred "Zuo" wrote in message news No, it must be if any of the numbers are greater than 60 or if the second longest is greater than 30. You must take into account all numbers all the time. "JLatham" wrote: For entries on row 2: =IF(OR(A260,B230),8,1) Ok, you may want a different number than 1 for the other cost, but I'm trying to attract customers for you. "Zuo" wrote: I need to satisfy the following condition: If the longest side of a box is greater than 60 or its second longest side is greater than 30, then charge $8. I have the Length, Width and Height measurements of each package in columns A,B, C. Example ABC 59,35,15 Thanks in advance for the help. Regards, ZUO . |
#9
|
|||
|
|||
Satisfying two conditions?
You're welcome, thanks for the feedback.
Fred "Zuo" wrote in message ... I have to give it to Fred Smith. That is what I needed, but thank you all very much for trying to help. All your help is very much appreciated. "Fred Smith" wrote: =IF(OR(MAX(A2:C2)60,LARGE(A2:C2,2)30),8,0) Regards, Fred "Zuo" wrote in message news No, it must be if any of the numbers are greater than 60 or if the second longest is greater than 30. You must take into account all numbers all the time. "JLatham" wrote: For entries on row 2: =IF(OR(A260,B230),8,1) Ok, you may want a different number than 1 for the other cost, but I'm trying to attract customers for you. "Zuo" wrote: I need to satisfy the following condition: If the longest side of a box is greater than 60 or its second longest side is greater than 30, then charge $8. I have the Length, Width and Height measurements of each package in columns A,B, C. Example ABC 59,35,15 Thanks in advance for the help. Regards, ZUO . |
Thread Tools | |
Display Modes | |
|
|