Rounding Time

The function is designed to cater for any numeric data type, not just
date/time values, which is why its arguments are declared as Double. In your
case it just so happens that you dealing with date/time values, so it make
sense to declare the variable for the value to be passed to the function as
Date. A date/time value is implemented as a 64 bit floating point number in
fact; we just normally see it in a date/time format.

In the original thread in which I posted this function there was subsequent
input from David Fenton, who made pertinent points about the advisability of
breaking the expression down and assigning the result of each constituent
operation to its own variable to avoid rounding errors. This lead to the
amendment of the function to:

Public Function RoundToInterval(dblVal As Double, _
dblTo As Double, _
Optional blnUp As Boolean = True) As Double

' rounds up by default.
' to round down pass False into function as
' optional UpDown argument

Dim intUpDown As Integer
Dim lngTestValue As Long
Dim dblTestValue As Double
Dim dblDenominator As Double

If blnUp Then
intUpDown = -1
Else
intUpDown = 1
End If

dblDenominator = intUpDown * dblTo
dblTestValue = dblVal / dblDenominator
lngTestValue = Int(dblTestValue)
RoundToInterval = intUpDown * lngTestValue * dblTo

End Function

It would be called in the same way, e.g. to round up, which is the default:

CDate(RoundToInterval(#8:14:59#,#00:15:00#))

or to round down:

CDate(RoundToInterval(#8:14:59#,#00:15:00#,False))

Ken Sheridan
Stafford, England

Bre-x wrote:
Hi

You are declaring the dTime as a Date Variable
the first variable that the RoundTo Function is expecting is a Double

I am missing something here?

Literal example
CDate(Roundto(#8:14:59#,#00:15:00#))
[quoted text clipped - 3 lines]
dTime = #8:14:59#
CDate(Roundto(dTime,#00:15:00#))

Public Function RoundTo(dblVal As Double _
, dblTo As Double _
, Optional intUpDown As Integer = -1) As Double

' rounds up by default.
' to round down pass 1 into function as
' optional intUpDown argument.
RoundTo = intUpDown * (Int(dblVal / (intUpDown * dblTo))) * dblTo

--
Message posted via AccessMonster.com
http://www.accessmonster.com/Uwe/For...arted/201005/1