If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. |
|
|
Thread Tools | Display Modes |
#1
|
|||
|
|||
DCOUNT Help
I am using the output from a combobox as a variable in a database formula
(DCOUNT). The variable is a name. My problem occurs when one name is used that is also part of another name in the database. Example: Luc will return counts not just for Luc but also Lucinda. How can I get DCOUNT to return just Luc counts? Additional: There are actually several combo boxes all supplying variables to the DCOUNT criteria; there are at least two variables, name and rating, and can be more, such as location, start date, end date, etc. A two variable example could be to return a count of the number of 5's in one column for the name Luc that is in another column. DCOUNT(Reference!$L$1:$AK$10000,Reference!AA$1,Ref erence!$A$10022:$K$10023) Here L1:AK10000 is the database, AA1 is the column of rating numbers, and A10022:K10023 lists the column headers and contains the criteria. Thank you very much! (I did not find an answer in the help file or forum search but I am no expert.) : ) Rob |
#2
|
|||
|
|||
DCOUNT Help
Try '=Luc
"Rob B." wrote: I am using the output from a combobox as a variable in a database formula (DCOUNT). The variable is a name. My problem occurs when one name is used that is also part of another name in the database. Example: Luc will return counts not just for Luc but also Lucinda. How can I get DCOUNT to return just Luc counts? Additional: There are actually several combo boxes all supplying variables to the DCOUNT criteria; there are at least two variables, name and rating, and can be more, such as location, start date, end date, etc. A two variable example could be to return a count of the number of 5's in one column for the name Luc that is in another column. DCOUNT(Reference!$L$1:$AK$10000,Reference!AA$1,Ref erence!$A$10022:$K$10023) Here L1:AK10000 is the database, AA1 is the column of rating numbers, and A10022:K10023 lists the column headers and contains the criteria. Thank you very much! (I did not find an answer in the help file or forum search but I am no expert.) : ) Rob |
#3
|
|||
|
|||
DCOUNT Help
Thank you very much bapeltzer! That works. : )
....now I just need to work converting the name into the name with '= in front of it, but it is now doable! Rob "bapeltzer" wrote: Try '=Luc "Rob B." wrote: I am using the output from a combobox as a variable in a database formula (DCOUNT). The variable is a name. My problem occurs when one name is used that is also part of another name in the database. Example: Luc will return counts not just for Luc but also Lucinda. How can I get DCOUNT to return just Luc counts? Additional: There are actually several combo boxes all supplying variables to the DCOUNT criteria; there are at least two variables, name and rating, and can be more, such as location, start date, end date, etc. A two variable example could be to return a count of the number of 5's in one column for the name Luc that is in another column. DCOUNT(Reference!$L$1:$AK$10000,Reference!AA$1,Ref erence!$A$10022:$K$10023) Here L1:AK10000 is the database, AA1 is the column of rating numbers, and A10022:K10023 lists the column headers and contains the criteria. Thank you very much! (I did not find an answer in the help file or forum search but I am no expert.) : ) Rob |
Thread Tools | |
Display Modes | |
|
|