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#1




Formula is sending me over the edge
This formula works when 47780 is input into D8, however,
it does not work if C,P or 53S is in D9: =IF(OR(AND('Appendix B'!D8="(47780)",J19K190),AND(OR ('Appendix B'!D9="C",'Appendix B'!D9="P",'Appendix B'! D9="53S"),J19K190)),0,+J19K19) This OTHER formula works when P (just an examplesame formula is used for C and 53S. =IF(ISNUMBER(FIND("P",'Appendix B'!D9)),'Appendix B'!D42,0) I need to incorporte the IF(ISNUMBER(FIND("P",'Appendix B'! D9... formula into the existing 1st formula for C,P, 53S and can't do it. Please help if you can. Thanks in advance. 
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#2




Formula is sending me over the edge
If 47780 is in D8 and C, P, or 53S is in D9, what do you expect the result
to be? Your current formula evaluates as TRUE if D8 contains 47780 and/or D9 contains C, P, or 53S. For any of these combinations, the result, in accordance with your formula, will be 0. If D8 does not contain 47780 and D9 does not contain C, P, or 53S then the formula evaluates as FALSE and J19K19 will be returned. Are you trying to come up with something else? Also, how do you want to incorporate the ISNUMBER formula into your original formula? What is the purpose? Post back and maybe we can find the right answer.  Michael J. Malinsky Pittsburgh, PA "I am a bear of very little brain, and long words bother me."  AA Milne, Winnie the Pooh wrote in message ... This formula works when 47780 is input into D8, however, it does not work if C,P or 53S is in D9: =IF(OR(AND('Appendix B'!D8="(47780)",J19K190),AND(OR ('Appendix B'!D9="C",'Appendix B'!D9="P",'Appendix B'! D9="53S"),J19K190)),0,+J19K19) This OTHER formula works when P (just an examplesame formula is used for C and 53S. =IF(ISNUMBER(FIND("P",'Appendix B'!D9)),'Appendix B'!D42,0) I need to incorporte the IF(ISNUMBER(FIND("P",'Appendix B'! D9... formula into the existing 1st formula for C,P, 53S and can't do it. Please help if you can. Thanks in advance. 
#3




Formula is sending me over the edge
Michael
Thanks for your response What I'm trying to accomplish is that if D8=47780 OR D9=C or P or 53S AND if J19K19 is greater than 0, then return 0 (true) otherwise return +J19 K19)(false), does this help? The problem is that in D9 the C,P could have something preceeding it (i.e., 26P), and the 53 could have something after it rather than the S, that is why without ISNUMBER, it doesn't recognize the C or P or 53S? Thank you for helping. Original Message If 47780 is in D8 and C, P, or 53S is in D9, what do you expect the result to be? Your current formula evaluates as TRUE if D8 contains 47780 and/or D9 contains C, P, or 53S. For any of these combinations, the result, in accordance with your formula, will be 0. If D8 does not contain 47780 and D9 does not contain C, P, or 53S then the formula evaluates as FALSE and J19K19 will be returned. Are you trying to come up with something else? Also, how do you want to incorporate the ISNUMBER formula into your original formula? What is the purpose? Post back and maybe we can find the right answer.  Michael J. Malinsky Pittsburgh, PA "I am a bear of very little brain, and long words bother me."  AA Milne, Winnie the Pooh wrote in message ... This formula works when 47780 is input into D8, however, it does not work if C,P or 53S is in D9: =IF(OR(AND('Appendix B'!D8="(47780)",J19K190),AND(OR ('Appendix B'!D9="C",'Appendix B'!D9="P",'Appendix B'! D9="53S"),J19K190)),0,+J19K19) This OTHER formula works when P (just an examplesame formula is used for C and 53S. =IF(ISNUMBER(FIND("P",'Appendix B'!D9)),'Appendix B'! D42,0) I need to incorporte the IF(ISNUMBER(FIND("P",'Appendix B'! D9... formula into the existing 1st formula for C,P, 53S and can't do it. Please help if you can. Thanks in advance. . 
#4




Formula is sending me over the edge
Michael,
Because of your note, I had to rethink what I was doing and Lo and Behold, I got the formula to work It's below for your future reference. Thanks a million times over. =IF(OR(AND('Appendix B'!D8="(47780)",J19K190),(ISNUMBER (FIND("53",'Appendix B'!D9))),(ISNUMBER(FIND("C",'Appendix B'!D9))),(ISNUMBER(FIND("P",'Appendix B'!D9)))*AND(J19 K190)),0,+J19K19) Original Message If 47780 is in D8 and C, P, or 53S is in D9, what do you expect the result to be? Your current formula evaluates as TRUE if D8 contains 47780 and/or D9 contains C, P, or 53S. For any of these combinations, the result, in accordance with your formula, will be 0. If D8 does not contain 47780 and D9 does not contain C, P, or 53S then the formula evaluates as FALSE and J19K19 will be returned. Are you trying to come up with something else? Also, how do you want to incorporate the ISNUMBER formula into your original formula? What is the purpose? Post back and maybe we can find the right answer.  Michael J. Malinsky Pittsburgh, PA "I am a bear of very little brain, and long words bother me."  AA Milne, Winnie the Pooh wrote in message ... This formula works when 47780 is input into D8, however, it does not work if C,P or 53S is in D9: =IF(OR(AND('Appendix B'!D8="(47780)",J19K190),AND(OR ('Appendix B'!D9="C",'Appendix B'!D9="P",'Appendix B'! D9="53S"),J19K190)),0,+J19K19) This OTHER formula works when P (just an examplesame formula is used for C and 53S. =IF(ISNUMBER(FIND("P",'Appendix B'!D9)),'Appendix B'! D42,0) I need to incorporte the IF(ISNUMBER(FIND("P",'Appendix B'! D9... formula into the existing 1st formula for C,P, 53S and can't do it. Please help if you can. Thanks in advance. . 
#5




Formula is sending me over the edge
" wrote...
Because of your note, I had to rethink what I was doing and Lo and Behold, I got the formula to work It's below for your future reference. Thanks a million times over. =IF(OR(AND('Appendix B'!D8="(47780)",J19K190), (ISNUMBER(FIND("53",'Appendix B'!D9))), (ISNUMBER(FIND("C",'Appendix B'!D9))), (ISNUMBER(FIND("P",'Appendix B'!D9))) *AND(J19K190)),0,+J19K19) Indenting terms with underscores, this becomes IF( __OR( ____AND( ______'Appendix B'!D8="(47780)", ______J19K190 ____), ____(ISNUMBER(FIND("53",'Appendix B'!D9))), ____(ISNUMBER(FIND("C",'Appendix B'!D9))), ____(ISNUMBER(FIND("P",'Appendix B'!D9)))*AND(J19K190) __), __0, __+J19K19 ) Do you really want to apply the AND(J19K190) test only when 'Appendix B'!D9 contains 'P'? That's what your formula does. Your original formula, =IF(OR(AND('Appendix B'!D8="(47780)",J19K190), AND(OR('Appendix B'!D9="C",'Appendix B'!D9="P", 'Appendix B'!D9="53S"),J19K190)),0,+J19K19) makes it appear you want to apply the J19K190 test to all 'Appendix B'!D9 cases. Starting with your original formula, you could try =IF(AND(J19K19,OR('Appendix B'!D8="(47780)", SUM(COUNTIF('Appendix B'!D9,"*"&{"C","P","53"}&"*")))),0,J19K19)  To toppost is human, to bottompost and snip is sublime. 
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