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"Modulas" Function
In Excel there is a "MOD" function which is described as "find the remainder
from wholly dividing an amount by a variable" Is there such a thing in Access? -- A MACKENZIE, CMA, MBA |
#2
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"Modulas" Function
aMack wrote:
In Excel there is a "MOD" function which is described as "find the remainder from wholly dividing an amount by a variable" Is there such a thing in Access? Yep... 3 mod 2 returns 1 -- Rick Brandt, Microsoft Access MVP Email (as appropriate) to... RBrandt at Hunter dot com |
#3
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"Modulas" Function
To get the most benefit from the Mod function, you need to wear bell bottom
pants and an Afro hairdo. "Rick Brandt" wrote: aMack wrote: In Excel there is a "MOD" function which is described as "find the remainder from wholly dividing an amount by a variable" Is there such a thing in Access? Yep... 3 mod 2 returns 1 -- Rick Brandt, Microsoft Access MVP Email (as appropriate) to... RBrandt at Hunter dot com |
#4
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"Modulas" Function
I am trying to run this calc in a query.
It gives me a blank result: ((1st Value]+[2nd Value]),mod,11) should give me 4 if Total Value = 6692 What am I doing wrong? Can this be run in an update query? -- A MACKENZIE, CMA, MBA "Rick Brandt" wrote: aMack wrote: In Excel there is a "MOD" function which is described as "find the remainder from wholly dividing an amount by a variable" Is there such a thing in Access? Yep... 3 mod 2 returns 1 -- Rick Brandt, Microsoft Access MVP Email (as appropriate) to... RBrandt at Hunter dot com |
#5
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"Modulas" Function
Get rid of the commas:
((1st Value]+[2nd Value]) mod 11) -- --Roger Carlson MS Access MVP Access Database Samples: www.rogersaccesslibrary.com Want answers to your Access questions in your Email? Free subscription: http://peach.ease.lsoft.com/scripts/...UBED1=ACCESS-L "aMack" wrote in message ... I am trying to run this calc in a query. It gives me a blank result: ((1st Value]+[2nd Value]),mod,11) should give me 4 if Total Value = 6692 What am I doing wrong? Can this be run in an update query? -- A MACKENZIE, CMA, MBA "Rick Brandt" wrote: aMack wrote: In Excel there is a "MOD" function which is described as "find the remainder from wholly dividing an amount by a variable" Is there such a thing in Access? Yep... 3 mod 2 returns 1 -- Rick Brandt, Microsoft Access MVP Email (as appropriate) to... RBrandt at Hunter dot com |
#6
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"Modulas" Function
YESSSSS!!!!!!!!!!
Thanks -- A MACKENZIE, CMA, MBA "Roger Carlson" wrote: Get rid of the commas: ((1st Value]+[2nd Value]) mod 11) -- --Roger Carlson MS Access MVP Access Database Samples: www.rogersaccesslibrary.com Want answers to your Access questions in your Email? Free subscription: http://peach.ease.lsoft.com/scripts/...UBED1=ACCESS-L "aMack" wrote in message ... I am trying to run this calc in a query. It gives me a blank result: ((1st Value]+[2nd Value]),mod,11) should give me 4 if Total Value = 6692 What am I doing wrong? Can this be run in an update query? -- A MACKENZIE, CMA, MBA "Rick Brandt" wrote: aMack wrote: In Excel there is a "MOD" function which is described as "find the remainder from wholly dividing an amount by a variable" Is there such a thing in Access? Yep... 3 mod 2 returns 1 -- Rick Brandt, Microsoft Access MVP Email (as appropriate) to... RBrandt at Hunter dot com |
#7
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"Modulas" Function
To get the most benefit from the Mod function, you need to wear bell
bottom pants and an Afro hairdo. It also helps to have been born prior to 1960 -- Lynn Trapp Microsoft MVP (Access) www.ltcomputerdesigns.com |
#8
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"Modulas" Function
On Wed, 22 Nov 2006 16:27:05 -0600, "Lynn Trapp"
wrote: To get the most benefit from the Mod function, you need to wear bell bottom pants and an Afro hairdo. It also helps to have been born prior to 1960 Never trust anyone over 46! updated from an earlier version... John W. Vinson[MVP] |
#9
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"Modulas" Function
"Lynn Trapp" wrote in message ... To get the most benefit from the Mod function, you need to wear bell bottom pants and an Afro hairdo. It also helps to have been born prior to 1960 Or just to have seen the movie! :-) http://en.wikipedia.org/wiki/Quadrophenia_%28film%29 -- Brendan Reynolds Access MVP |
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