A Microsoft Office (Excel, Word) forum. OfficeFrustration

If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below.

Go Back   Home » OfficeFrustration forum » Microsoft Excel » Worksheet Functions
Site Map Home Register Authors List Search Today's Posts Mark Forums Read  

Simple find with right function



 
 
Thread Tools Display Modes
  #11  
Old November 2nd, 2005, 04:13 AM
Biff
external usenet poster
 
Posts: n/a
Default Simple find with right function

Hi!

Am I missing something, or does RIGHT have some obscure problem that
the experts are aware of and others are not?


No, not really. Using RIGHT is perfectly acceptable but consider these
differences (and this is what separates the "experts" from the rest of us!):

=RIGHT(A1,LEN(A1)-FIND("~",SUBSTITUTE(A1,"/","~",LEN(A1)-LEN(SUBSTITUTE(A1,"/","")))))

That formula contains 7 function calls and takes 86 keystrokes.

=MID(A1,FIND("~",SUBSTITUTE(A1,"/","~",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))))+1,255)

This formula has 6 function calls and takes 82 keystrokes.

Biff

"DOR" wrote in message
oups.com...
Biff,

I notice that 3 different responders to this request suggest the MID
function with some high number of characters to return, rather than the
RIGHT function as in :

=RIGHT(A1,LEN(A1)-FIND("~",SUBSTITUTE(A1,"/","~",LEN(A1)-LEN(SUBSTITUTE(A1,"/","")))))

which seems to work well enough and doesn't need the catch-all value of
1,255 or whatever else.

Am I missing something, or does RIGHT have some obscure problem that
the experts are aware of and others are not?



  #12  
Old November 2nd, 2005, 04:31 AM
DOR
external usenet poster
 
Posts: n/a
Default Simple find with right function

Biff and Peo,

Thank you both - flexibility and efficiency trump intuitivity ...

I guess Biff could have saved a few keystrokes and a few interpreter
cycles by leaving out the comma in 1,255 or using a smaller number g
....

DOR

  #13  
Old November 2nd, 2005, 04:46 AM
Biff
external usenet poster
 
Posts: n/a
Default Simple find with right function

I guess Biff could have saved a few keystrokes and a few interpreter
cycles by leaving out the comma in 1,255 or using a smaller number g


The comma is the argument delimiter in the MID function!

=MID(A1,FIND("~",SUBSTITUTE(A1,"/","~",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))))+1,255)

FIND("~",SUBSTITUTE(A1,"/","~",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))))+1

That is the 2nd argument which tells MID at what position in the string to
use as the extraction starting point.

255 is the 3rd argument which tells MID how many characters to return.

255 is used because you may never know exactly how many characters there are
to the end of the string.

Biff

"DOR" wrote in message
oups.com...
Biff and Peo,

Thank you both - flexibility and efficiency trump intuitivity ...

I guess Biff could have saved a few keystrokes and a few interpreter
cycles by leaving out the comma in 1,255 or using a smaller number g
...

DOR



  #14  
Old November 2nd, 2005, 07:02 AM
Harlan Grove
external usenet poster
 
Posts: n/a
Default Simple find with right function

DOR wrote...
Thank you both - flexibility and efficiency trump intuitivity ...

....

Intuitivity, if it were an English word, I suppose would mean
intuitiveness. Intuitiveness is subjective.

Shorter formulas may not matter much when the overall formula length is
fewer than 100 characters, but small formulas have a bad habbit of
becoming small pieces of much longer formulas, and when formulas grow
to several hundred characters and many repeated expressions, it's good
to know how to shorten them.

Also, Excel's substring matching functions only return position from
the left of the string. If one wants all characters to the right of a
given position (measured from the left), and if Excel's substring
functions were picky, there'd be two ways to return it:

RIGHT(string,LEN(string)-position)

and

MID(string,position+1,LEN(string)-position)

Happily, these functions aren't picky, and effectively truncate their
length arguments at the length of their string argument. Which means
the MID call above is equivalent to

MID(string,position+1,LEN(string))

and

MID(string,position+1,BIGNUMBER)

where BIGNUMBER is a placeholder for any moderately large positive
whole number. And, FWIW, VBA's Mid function doesn't even require a 3rd
argument to return the right substring beginning at the position given
by its second argument. Using the worksheet MID function with a large
3rd argument is the simplest way to mimick VBA Mid semantics.

That said, this is a situation in which using RIGHT may be more
suitable. The shortest formula not using defined names may be the array
formula

=RIGHT(A1,MATCH("/",MID(A1,LEN(A1)-ROW(INDIRECT("1:"&LEN(A1)))+1,1),0)-1)

Using defined names, e.g., s referring to =ROW(INDIRECT("1:1024")), the
shortest formula would be

=MID(A1,LOOKUP(2,1/(MID("/"&A1,s,1)="/"),s),1024)

which should return the whole string if there are no /s in it.

If you want to get exotic, download and install Laurent Longre's
MOREFUNC.XLL add-in and use

=WMID(A11,-1,1,"/")

and learn the joys of using negative integers to index from right to
left.

  #15  
Old November 2nd, 2005, 08:06 PM
DOR
external usenet poster
 
Posts: n/a
Default Simple find with right function

But of course, Biff, but of course ...

 




Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is Off
HTML code is Off
Forum Jump

Similar Threads
Thread Thread Starter Forum Replies Last Post
Simple function problem headly Worksheet Functions 2 July 7th, 2005 08:50 AM
Excel option to store trendline's coefficients in cells for use Miguel Saldana Charts and Charting 9 June 20th, 2005 08:45 PM
How to use FIND Function in PP VB jimr Powerpoint 3 April 30th, 2005 02:46 AM
Outlook bug: views do not work after simple find. N. P. General Discussion 1 March 11th, 2005 05:59 PM
decipher log of scanpst.exe km General Discussion 0 July 18th, 2004 09:00 AM


All times are GMT +1. The time now is 12:25 AM.


Powered by vBulletin® Version 3.6.4
Copyright ©2000 - 2024, Jelsoft Enterprises Ltd.
Copyright ©2004-2024 OfficeFrustration.
The comments are property of their posters.