Shape Range
Luke,
Thank you for your input, when I attempt to qualify that way, the code
does run but the shapes don't fill with the color passed. I would
have assumed it is the correct way to code it but with an unexpected
result.
Thanks again for your response.
Mark
On Apr 21, 4:37*pm, "Luke M" wrote:
'Does this not work?
* * * * With shtMap.Shapes(strShapeNum).ShapeRange
* * * * * * .Fill.ForeColor.RGB = dColor
* * * * * * .Fill.Visible = msoTrue
* * * * * * .Fill.Solid
* * * * End With
--
Best Regards,
Luke M"kuhrty" wrote in message
...
Below is a subroutine that passes in 2 variables. *I am concerned with
the word "Selection" used for ShapeRange and would prefer to eliminate
it. *All my attemptes have resulted in errors. *I want qualify the
code to prevent error.
Is selection a keyword for ShapeRange or is there a way to qualify it?
Thanks in advance.
Public Sub CountryColor(ByVal strCountry As String, _
* * * * * * * * * * * *ByVal dColor As Double)
* *Dim shtMap As Worksheet, rgData As Range, strShapeNum As String
* *Dim i As Integer, dColor1 As Double
* *Set shtMap =
ThisWorkbook.Application.ThisWorkbook.Worksheets(" Map")
* *Set rgData =
ThisWorkbook.Application.ThisWorkbook.Worksheets(" Data").Range("RegionCount*ryData")
* *On Error Resume Next
* *shtMap.Select
* *For i = 1 To rgData.Rows.Count
* * * *strShapeNum = rgData.Cells(i, 3).Value
* * * *shtMap.Shapes(strShapeNum).Select
* * * 'This is my issue"
* * * *With Selection.ShapeRange
* * * * * *.Fill.ForeColor.RGB = dColor
* * * * * *.Fill.Visible = msoTrue
* * * * * *.Fill.Solid
* * * *End With
* *Next i
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