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Old March 22nd, 2010, 02:07 AM posted to microsoft.public.excel.newusers
Ron Rosenfeld
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Posts: 3,719
Default Is this a trim issue

On Sun, 21 Mar 2010 18:21:44 -0700 (PDT), Box666
wrote:

On 21 Mar, 19:50, Ron Rosenfeld wrote:
On Sun, 21 Mar 2010 12:02:35 -0700 (PDT), Box666
wrote:





I have been given somebody's library to catalogue and provide a search
engine for. At the moment it is in text format in column A.


The following is an example.


G:\Books\N O P\Nigel R Clough\Nigel R Clough - How To Make and Use
Mirrors.pdf


Or sometimes it appears as
G:\Books\N O P\Nigel R Clough - How To Make and Use Mirrors.pdf


So I want to move everything to the right of the last “\” into column
B and the rest into column C. So in the first example above:-


Nigel R Clough - How To Make and Use Mirrors.pdf *would be in Column B
And
G:\Books\N O P\Nigel R Clough\ * * *would be on Column C.


While in the 2nd example
Nigel R Clough - How To Make and Use Mirrors.pdf *would be in Column B
And
G:\Books\N O P\ * * *would be on Column C.


Any help in this matter would be much appreciated.


B1:

=TRIM(RIGHT(SUBSTITUTE(A1,"\",REPT(" ",255)),255))

C1:

=LEFT(A1,FIND(CHAR(1),SUBSTITUTE(A1,"\",CHAR(1),LE N(A1)-LEN(SUBSTITUTE(A1,"*\","")))))

--ron- Hide quoted text -

- Show quoted text -


Ron,
Thank you B1 works great but C1 brings up a #VALUE! error


I don't know why or how the C1 formula got changed from what I posted. Must be
an idiosyncrasy of how you are accessing the newsgroup.

In any event, there should not be a hyphen prior to the slash in the last
substitute function.

Perhaps if I put it on two lines, it'll "come through" properly:

=LEFT(A1,FIND(CHAR(1),SUBSTITUTE(
A1,"\",CHAR(1),LEN(A1)-LEN(SUBSTITUTE(A1,"\","")))))

--ron